2x^2-18x-1944=0

Solution for 2x^2-18x-1944=0 equation:

2x^2-18x-1944=0

a = 2; b = -18; c = -1944;
Δ = b2-4ac
Δ = -182-4·2·(-1944)
Δ = 15876
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{15876}=126$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-126}{2*2}=\frac{-108}{4}
=-27
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+126}{2*2}=\frac{144}{4}
=36
$